## Sunday, October 16, 2011

### Manolas Emmanuel (5), Problems from Jesi, part 2

We continue with the rest of the compositions with which I participated in various composition tourneys in Jesi, Italy, during the World Chess Compositions Congress.
When a composition has a defect or it happens that the judge dislikes it or it is weaker than the compositions of other composers, then it does not take a distinction. We do our best to create a very nice position but, as it happens in life, this is not always possible. Some of the compositions, when we examine them later without pressure (and with more experience), can be improved. This is something that the experienced judges see or feel, and that is why their opinion is useful.
In a previous post we saw five compositions, let us see now and the rest of them.

### 11th Japanese Sake / 3rd Brazilian Cachaça Tourney

Theme : Series selfmate / selfstalemate, (ss#n, ss=n), with Reversible Promotion. Neither fairy pieces nor other fairy conditions are allowed except for Maximummer.

In a Series self(stale)mate of n moves, the White alone makes n-1 moves without checking and in the last move the immobility of Black is raised and the Black achieves the goal (mate or stalemate).
We know that a white pawn starts from the second line and is promoted in the eighth line (for black : seventh and first, respectively). With the condition of Reversible Promotion, a white promoted piece stepping on the second line (for black : seventh) becomes pawn again.

 k7/7P/p2pp3/K1ppp3/P1p5/8/1s2p3/1r3bb1 w (3+13) Problem-502 Kostas Prentos - Manolas Emmanuel First Honourable Mention ss#18, Reversible Promotion, Maximummer, 2 solutions 1.h8=B 2.Bxe5 3.Bxb2=P 4.b4 5.bxc5 6.c6 7.c7 8.c8=B 9.Bd7 10.Bb5 11.Bxc4 12.Bxe2=P 13.e4 14.e5 15.exd6 16.d7 17.d8=B 18.Bb6 Bxb6# 1.h8=S 2.Sg6 3.Sf4 4.Sxe2=P 5.e4 6.exd5 7.dxe6 8.e7 9.e8=S 10.Sxd6 11.Sxc4 12.Sxb2=P 13.b4 14.bxc5 15.c6 16.c7 17.c8=S 18.Sb6+ Bxb6#

The Japanese Judge Tadashi Wakashima commented : "Very nice presentation in two solutions of three promotions and two reversals (wB in the first solution and wS in the second one).".
The price was accompanied by a bottle of Japanese Sake.

 8/q3r2P/1b4p1/pb6/2p3p1/2p2k1p/1s1r1p1P/5K2 w (3+14) Problem-503 Manolas Emmanuel Third Honourable Mention ss#27, Reversible Promotion 1.h8=B 2.Bxc3 3.Bxb2=P 4.b4 5.bxa5 6.axb6 7.bxa7 8.a8=R 9.Rd8 10.Rxd2=P 11.d4 12.d5 13.d6 14.d7 15.d8=S 16.Se6 17.Sf4 18.Sxh3 19.Sf4 20.h4 21.h5 22.hxg6 23.g7 24.g8=Q 25.Qxc4 26.Se6 27.Qd3+ Bxd3#

The Japanese Judge Tadashi Wakashima commented : "Allumwandlung with two pawns".
The price was accompanied by a bottle of Brazilian Cachaça.

I worked several days to make this problem. The computer software were not of real help because the moves were too many and the time needed was too much (about 45 hours). At the end the very fast solver Kostas Prentos helped me with the validity checking, and I thank him.

The plan of White, to check with the Queen at d3 forcing bBb5 to capture it giving mate, has some obstacles. First there is no Queen, second many black pieces (Qa7, Bb6, Sb2, c4, Rd2, Re7) can intervene to a threat of mate from d3, and furthermore bK has a flight f4. And the bBb5 cannot guard d3 because bPc4 stands in the way.
The pawn bPg6 is needed for column change of wPh2 going to be promoted at g8, but if it was positioned at g5, a second unwanted solution appears with 1.h8=S.
The key should not be promotion to Queen because the second move 2.Qxc3 would check the bK.
Similarly for the move 8.a8=R, if we had a promotion to Queen it would check the bK. And then only the path Ra8-d8-xd2=P is valid, not via a2!
The Queen will be needed at the end and also a piece to guard f4. If the pawn wPh2 should be freed, we observe that bPh3 can be captured only by a Knight without giving check to bK!

In the fourteenth move the Knight cannot capture the rook (14.dxe7?) and also solve the problem in 27 moves. So bypasses it and postpones the closing of the line of bR (and also guarding f4 from there) for later. How much later?
Before e6 is occupied, the Queen must pass over it, 25.Qg8xc4, and only then 26.Sf4-e6.
Finally in this composition we have the four promotions (=allumwandlung), Bishop, Rook, Knight, Queen.

 8/1Pq5/8/8/4p1pp/4r2k/3spr1p/3bbs1K w (2+13) Problem-504 Manolas Emmanuel Third Commendation ss#27, Reversible Promotion 1.b8=B 2.Ba7 3.Bxe3 4.Bxd2=P 5.d4 6.d5 7.d6 8.dxc7 9.c8=R 10.Rg8 11.Rxg4 12.Rxe4 13.Rxe2=P 14.e4 15.e5 16.e6 17.e7 18.e8=R 19.Rxe1 20.Rxf1 21.Rxf2=P 22.f4 23.f5 24.f6 25.f7 26.f8=Q 27.Qf3+ Bxf3#

The Japanese Judge Tadashi Wakashima commented : "Three promotions and three reversals by a single pawn".
Here I have gathered the maximum number of obstacles (without promoted black force) to the White plan.

### Thematic Tourney «The Urals Problemist» - 2011

Theme: Selfmate (s#3-5). Recovery of the initial white or black battery.

 7b/7p/3S1k1P/2P4P/4R3/pp2pPQ1/p4p2/Kb3r2 w (8+10) Problem-505 Manolas Emmanuel Version, Dedicated to Andrey Selivanov s#4 Tries : {1.f4? [2.Qg6+ hxg6 3.Re6+ Kxe6#] Bg7!}, {1.Re8? [2.Qf4+ Bf5#] e2!} Key : 1.Re5! [2.Qf4+ Bf5#] e2 2.Qh4+ Kxe5 3.Qe4+ Kf6 4.Qe7+ Kxe7#

The Dedication is because the Judge Andrey Selivanov found that the initial position I submitted {7b/8/3S1k1P/2P3RP/Q7/pp2p3/p4p2/Kb3r2 w} had a flaw (unprovided check 1...Kxf5+ in the set play). The version here is corrected.

I hope that I have given you an idea of the creativity frenzy that exists during the world chess composition congress. Think about several other composing tourneys I did not participated and the important fact that there were many composers there better than me.

## Saturday, October 15, 2011

### Manolas Emmanuel (4), Compositions from Jesi, part 1

In Jesi, Italy, I participated in some composition tourneys, sometimes with success sometimes without a distinction. I would like to present to you these compositions of mine. Two posts will be made.

### Quick Thematic Tourney (time : three hours)

a) Theme: Orthodox two-mover where at least two variations have the mating move starting from (or ending to) the same square.

 6s1/8/3SK3/8/1P1k3B/1R6/2P5/3rb3 w (6+4) Problem-497 Manolas Emmanuel #2 Tries : {1.Bd8? Bxb4!}, {1.Rh3? Bg3!} Key : 1.Rf3! zz 1…Sh6 / Se7 / Sf6 2.B(x)f6# 1…Bxh4 / Bg3 / Rd2 2.c3# 1…Bxb4 / Bc3 2.Bf2# 1…Bd2 / Ra1 / Rb1 / Rc1 / Rd3 2.Rxd3# 1…Bf2? 2.Bxf2# / c3# (dual)

Black correction. The move 1...Βc3 corrects the moves 1...Βxh4 and 1...Rd2. The move 1...Βd2 corrects the moves 1...Βxb4 and 1...Βc3.
Mirror mates.
No distinction.

b) Theme: Helpmate with two solutions (or twin), where in one a pawn A makes a single step and a pawn B makes a double step, and in the other the pawns exchange roles.

 1q2s3/8/2pkp3/K7/5P2/8/B2PP3/8 w (5+5) Problem-498 Manolas Emmanuel h#2, a) diagram, b) wBa2->f2 a) 1.Kc5 e3 2.Sd6 d4# b) 1.Kd5 d3 2.Qd6 e4#

Selfblock. Model mates. Dual avoidance.
No distinction.

### Azerbaijan Study Tourney

Theme : Sacrifice (with or without check) of a white chessman (piece of pawn) on a square guarded by two black chessmen.

 6S1/p2pPb2/P1kq2S1/P5B1/P1pP4/4r2p/2R4P/6K1 w (11+8) Problem-499 Manolas Emmanuel = (White plays and draws) 1.e8=Q (thematic) Rxe8 (1.e8=R? Qxg6 2.Rxe3 Bxg8 -+ or 2.d5+ Kd6 3.Rxe3 Qxg5+ 4.Kf2 Qf4+ 5.Rf3 Qd2+ 6.Kf1 Qxc3 7.Rxf7 Qxd3+ 8.Kf2 c3 -+) (1.Rxc4+ Bxc4 2.e8=Q Rxe8 3.S8e7+ Kc7 4.Bf4 Bd3 5.Bxd6+ Kxd6 6.Kf2 Be4 -+) 2.S8e7+ (thematic) Rxe7 3.Sxe7+ Kc7 4.Rxc4+ Bxc4 5.Bf4 Qxf4 6.Sd5+ Bxd5 =

The Judge decided that the thematic moves were not sacrificies and gave no distinction.
Later he send this problem to be published : [Olympiya Dunyasi No62 13-15.09.2011, problem 721].

### Second Bulgarian Wine Tourney

Theme : Helpmate two-movers with at least a Chameleon-piece (of type Q-S-B-R-Q). Other fairy pieces or conditions are not allowed.

 3b4/5p2/3r2Rq/5k2/5SS1/8/7P/6K1 w (5+5) Problem-500 Manolas Emmanuel Commendation h#2, 6 solutions, Chameleons wSf4, wSg4, bRd6, wRg6, bQh6, bBd8 1.Qh6-g5=S Sg4-f6=B 2.Sg5-e4=B Rg6-g5=Q# 1.Qh6xh2=S Sg4xh2=B 2. Rd6-d3=Q Sf4xd3=B# 1.Qh6-h4=S Rg6-e6=Q+ 2.Kg5 Sg4-h6=B# 1.Bd8-e7=R Sg4xh6=B 2.Re7-e4=Q Rg6-g5=Q# 1.Ke4 Rxd6=Q 2.f5 Sf4-g2=B# 1.Kxf4 Sxh6=B+ 2.Kf3 Rg6-g2=Q#

The Judge Diyan Konstadinov wrote [Six different solutions, but with Not homogeneous play].

### METAXA Tourney Jesi (Italy) 2011 in memoriam Albert H. KNIEST

The Greek Judge Pavlos Moutecidis (who has started the custom with local wines to accompany the prizes) asked the following.
Theme : Selfmate Maximummer with set play. No limit on the number of moves. The total number of pieces should not exceed 10. Other fairy conditions or pieces are not allowed.

 1q3k1K/8/8/3pp3/1r6/1P6/8/8 w (2+5) Problem-501 Manolas Emmanuel (original, please do not reprint) s#11, Maximummer Set play : 1…Rh4# Key : 1.Kh7! [2.Kh8 Rh4#] 1…Rh4+ 2.Kg6 Ra4 3.bxa4 Qb1+ 4.Kg5 Qh7 5.a5 Qb1 6.a6 Qh7 7.a7 Qb1 8.a8=R+ Qb8 9.Kh6 Qe8 10.Ra6 Qa4 11.Rg6 Qh4#
It is a Miniature, it has switchbacks of pieces, underpromotion, Pelle movement (done by a pinned piece).
It contains the theme white Chernous ("A white piece A theatens the black King. A black piece is self-pinned to stop the threat. Then the White unpins B, the piece A self-blocks the white King and the black B delivers mate"). (The theme Chernous has reversed colours).
No distinction.

I will post the second part very soon.