Saturday, February 28, 2015

Mr Spock and chess

On 27-02-2015 the actor Leonard Nimoy (1931-2015) left from this world. He was the Science Officer in the TV series Star Trek.

In the series Mr Spock played 3d chess. (At the photo, standing is the actor De Forest Kelley, 1920-1999).



A farewell by the chess cartoonist Wadalupe is this :


Wednesday, February 25, 2015

Chess composition, a point of view by Miro Brada

To some chess players the art of the chess composition is unknown or just an oddity. But, based on chess, there are two worlds
(a) the world of the over-the-board chess, where the novelty in moves is desirable but seldom happens because the players usually copy and repeat the known good moves. If a played chess game is similar to or exactly the same as an older one, there is no blame and the game is accepted.
(b) the world of the artistic chess composition, where the novelty is the rule, because the art creations must be original and unique. If a composed problem is similar to an older one, it is considered anticipated and then discarded.

The composer Miro Brada in an extended presentation (in English) reveals to us details of his life, from the time he could not appreciate the specialities of the chess composition until recently when he has become a multi-awarded composer. :
http://mirobrada.blogspot.co.uk/2013/10/chess-composition-as-art.html

Apart from his compositions, presented and explained, he describes similarities with other human activities, mental or athletic.
A point, which I found interesting, is this : In socialistic countries, where profit is not the goal and the opportunities are limited, the people develop their talents in other fields, one of which is chess composing.

Saturday, February 14, 2015

February 14th

Today, like every other day I would say, it is a holiday for people in love.
The stores offer for sale heart-shaped presents.

Those of you who love the chess problems, accept a composition with such a shape.

It is an easy twomover, and it is also the number 800 problem of the numbered problems of this blog, (many un-numbered problems have also appeared in Awards, Solving Contests etc).


Problem-800
Manolas Emmanuel (GRE)
original


8/3s1R2/2s1k1K1/2Q3p1/3p1b2/4p3/8/8 (3 + 7)
#2

Tries : {1.Rf6+? Sxf6!}, {1.Re7+? Sxe7+!}, {1.Qd5+? Kxd5!}, {1.Qxc6+? Bd6!}

Key : 1.Qf5+! Kd6 2.Rxd7#

Happy Valentine's Day!


Here follows a series of hearts that I found in the Internet.


8/3s1P2/2S1k1K1/2P3p1/3p1R2/4S3/8/8
 (6 + 4), #2
Problem-801

Schenkerik Csaba (from facebook, Judit Polgar Official)

Tries : {1.Re4+? Se5+!}, {1.f8=S+? Sxf8+!}

Key : 1.Rf6+! Sxf6 2.f8=S#



1S1R4/k1S1p3/P3K3/1P1P4/2P5/8/8/8
 (8 + 2), #2
Problem-802

Schenkerik Csaba (from facebook, Judit Polgar Official)

Key : 1.Sa8! Kxa8 2.Sc6#



8/3P1P2/2P1k1P1/2K3P1/3P1P2/4P3/8/8
 (9 + 1), #2
Problem-803

Unknown composer (from facebook, Judit Polgar Official)

Key : 1.f8=R! Ke7 2.Re8#



8/3s1P2/2S1k1K1/2P3p1/3p1R2/4S3/8/8
 (6 + 4), #2
Problem-804

Polgar Laszlo (from facebook, Judit Polgar Official)

Key : 1.Qxe5+! Sxe5 2.f5#


8/2bp1Sp1/2b1k1K1/2q3B1/3Q1P2/4S3/8/8
(6 + 6), #2
Problem-805

Benko Pal

Key : 1.Qd6+!, 1...Bxd6 2.Sd8#, 1...Qxd6 2.f5#



8/2P3P1/1p1P1K1b/1r1pQp1p/
1s5s/2R3R1/3SqS2/4k3
(9 + 10), #3
Problem-806

Loyd Sam

Κλειδί : 1.Rce3! [2.Rxe2#]
1...Bxe3 2.Rxe3 [3.Rxe2#] Qxe3 3.Qxe3#,
2...Kxd2 3.Qc3#, 2...Kxf2 3.Qg3#

1...Bg5+ 2.Rxg5 [3.Rxe2#] Qxe3 3.Qxe3#,
2...Kxd2 3.Qc3#

1...Bxg7+ 2.Kxg7 / Rxg7 [3.Rxe2#] Qxe3 3.Qxe3#,
2...Kxd2 3.Qc3#

1...Qxe3 2.Rxe3+ Kxd2 3.Qc3#,
2...Kxf2 3.Qg3#, 2...Bxe3 3.Qxe3#




Some more compositions by Diyan Kostadinov here [http://kobulchess.com/en/news/7-2011-07-31-17-09-09/188-valetinesday.html] and here [http://kobulchess.com/en/news/7-2011-07-31-17-09-09/767-happy-valentines-day.html].

Sunday, February 01, 2015

4th FIDE Cup

The results for the 4th FIDE Cup (from 01-II-2015 upto 01-IV-2015) [http://www.wfcc.ch/competitions/composing/fidewcc_2015/] have started to be published.

It is a contest for composers of all genres of chess problems. The compositions are very good and we congratulate all the participants, winners, judges, organisers.

A. Twomovers – Judge: Franz Pachl (Germany)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-a-twomovers.pdf

B. Threemovers – Judge: Jakov Vladimirov (Russia)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-B-threemovers.pdf

C. Moremovers – Judge: Juri Gordian (Ukraine)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-C-moremovers.pdf

D. Endgame Studies - Judge: Yochanan Afek (Israel)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-D-studies.pdf

E. Helpmates - Judge: Abdelaziz Onkoud (Morocco)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-E-helpmates.pdf
Here, among others, you may see the fourth prize awarded to (GRE) Kostas Prentos(GRE).

F. Selfmates - Judge: Sven Trommler (Germany)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-f-selfmates.pdf

G. Fairies - Judge: Tadashi Wakashima (Japan)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-G-fairies.pdf

H. Retros and Proofgames - Judge: Michel Caillaud (France)
http://www.wfcc.ch/wp-content/uploads/FIDE-World-Cup-2015-section-H-retros.pdf

Saturday, January 31, 2015

Adventure in composition with Andernach Lions

In this post we will observe the attempt for composing problems having specific fairy pieces, namely Andernach Lions.

Lion : Is a hurdle jumper, moves at Queen lines, jumps over a hurdle and steps on one of the empty squares (or captures a piece there) which are exactly behind the hurdle.
The "hurdle-color changing" Lion (or 
Andernach Lion) when passes over a hurdle changes the color of the hurdle (except it is a King or a neutral piece).


Last year we had seen, among the awarded problems in the World Congress on Chess Composition (WCCC) in Bern, the following problem with one Andernach Lion.
The composition tourney asked from the composers a helpmate two-mover with hurdle-color changing Lions. We had two ideas but the deadline was only three hours, so we barely had the time for checking one composition, the problem-776.

Problem-776
Manolas Emmanuel (GRE) and Prentos Kostas (GRE)
Commendation, Quick Composing Ty, WCCC 2014 Bern

2Sk4/3p4/8/3K4/8/8/1(whL)2r3/8 (3 + 3)
(hL hurdle-color changing Lion b2 + 0)
h#2, two solutions

1.Re2-f2 hLb2-g2(wRf2) 2.Kd8-e8 hLg2-a8#

1.Re2-e5+ hLb2-g7(wRe5) 2.Kd8xc8 Re5-e8#


The Judge wrote : "Nice miniature. The white rook and Lion exchange functions in the mate".


The second idea lead us to the Problem-795. The idea here was to put the black Lions as epaulets from both sides of the mating piece, so they cannot capture it. This is achieved with Orthogonal - Diagonal Transformation, as you can see in the solution. 

The prominent composer Kostas Prentos, international maitre and multi-champion of Greece in solving contests, has moved to Uinted States of America, that is why his name is appended with USA.

Problem-795
Prentos Kostas (USA) and Manolas Emmanuel (GRE)
Julia's Fairies No.593, 04-09-2014

8/8/(whL)5b1/2(bhL)p4/3pk3/1K6/1(bhL)P1r3/8 (3 + 7)
(hL, Andernach Lion a6 + b2 c5)
h#2, a) Diagram, b) wPc2 to g2

a)
1.hLc5-f2(wPd4) Kb3-c3 2.hLb2-d2(bPc2) hLa6-f1(wRe2)#
b)
1.hLc5-g5(wPd5) Rb3-c4 2.hLb2-g7(wPd4) hLa6-h6(wBg6)#


For this problem we had many comments, mainly because the black pieces bRe2 and bBg6 stayed inert, waiting to change color. It is not forbidden for black pieces to stay inactive in some of the solutions (for white pieces this is forbidden), nevertheless the composition could be altered.


The composer Ladislav Packa had proposed to us the idea to convert the inactive pieces to Andernach Lions. In the following Problem-796, besides Lions (moving in Queen lines) we use a Rook-Lion (moving in Rook lines). To achieve what we want, we start with a white move, so the problem is now h#2,5 .

Problem-796
Packa Ladislav and Prentos Kostas and Manolas Emmanuel
Pat a Mat No.90, December 2014, page 242 Problem No.790

7b/3(bhRL)4/2p1p3/4(bhL)(bhL)2/P1kpP(whL)2/8/2p1p3/4K3 (4 + 10)
(hL, Andernach Lion f4 + e5 f5)
(hRL, Andernach Rook-Lion 0 + d7)
h#2.5, two solutions

1…hLf4-c7(whLe5)+ 2.hRLd7-b7(bhLc7) Ke1xe2 3.hLf5-d7(wPe6) hLe5-b8(whLc7)#

1…hLf4-f7(whLf5)+ 2.hRLd7-g7(bhLf7) Ke1-d2 3.hLe5-e7(wPe6) hLf5-f8(whLf7)#


Here there is Orthogonal - Diagonal Transformation and the idea of Lions as epaulets is well presented.


Since the moves have become 2.5, the question arises if we can make something different for helpmate twomover. I have tried the position which is shown as Problem-797.

Problem-797
Manolas Emmanuel (GRE)
original

3K1(whL)2/8/8/2SP2(bhL)1/3k4/1P6/5br1/1s4B1 (6 + 5)
(Andernach Lion f8 + g5)
h#2, a) Diagram, b) bRg2 to b4

a)
1.hLg5xg1(wRg2) Rg2-g5 2.hLg1-a1(wSb1) hLf8-f1(wBf2)#
b)
1.hLg5xc5(bPd5) Bg1-h2 2.hLc5-e3 hLf8-a3(wRb4)#


Here we see the Orthogonal - Diagonal Transformation, but not the epaulets, which may be abandoned. Black pieces are used that stay inactive in some phase (not forbidden, but not economical enough), and the solutions have not the same number of color changing.


Maybe I can do better. Let us try a new position.

Problem-798
Manolas Emmanuel (GRE)
original

8/8/8/1(bhL)pk4/p7/4Kp2/1P2(bhL)1(bhL)1/8 (2 + 7)
(hL Andernach Lion 0 + b5 e2 g2)
h#2, a) diagram, b) bPa4 to e6

a)
1.hLg2-c2(whLe2) b2-b4 2.hLc2-c6(wPc5) hLe2-a6(whLb5)#
b)
1.hLb5-f1(whLe2) b2-b3 2.hLf1-f4(wPf3) hLe2-h2(whLg2)#


Here White has minimal force, just one Pawn, but he can find the required forces to make two mates, one in an orthogonal way and one in a diagonal way. In each solution there are three changes of color.


Can this become better? The answer is yes. 

Problem-799
Manolas Emmanuel (GRE) and Prentos Kostas (GRE)
dedicated to Ladislav Packa
The Problemist vol.25 No.1, January 2015, problem F3184
Commendation, vol.27 No.6, November 2019, p.242

4K3/8/8/1(bhL)pk1p2/p2p4/5p1(whL)/1p2(bhL)1(bhL)1/8 (2 + 10)
(hL Andernach Lion h3 + b5 e2 g2)
h#2, two solutions

1.hLg2-c2(whLe2) hLh3-e3(wPf3) 2.hLc2-c6(wPc5)+ hLe2-a6(whLb5)#

1.hLb5-f1(whLe2) hLh3-c8(wPf5) 2.hLf1-f4(wPf3) hLe2-h2(whLg2)#


The composition is not in a twin form, it has two solutions.
There is orthogonal - diagonal transformation.
White has only an Andernach Lion. In each solution there are four color changes and they are all necessary!

Comment by Judge Michal Dragoun : Full analogy in recolouring of the pieces.