Composers' cooperations (3)

In this post we will see five problems created by cooperative composers. In general, the chess composition is a lonely activity. Most of the time it is you and your chessboard, or even your computer running the proper software. But often the composers share an idea with someone else and the composition has more than one parents.
Who has done most of the work? Finally, it does not matter. The cooperation is worthwhile.
Whose name will be written at the top? We said, it does not matter. The main thing here is that the composers cooperate and sometimes they become friends.
There are in the chess history rare cases, where composers having together awarded compositions, at the end they do not speak to each other.

Problem-710 Ioannis Kalkavouras, Greece Emmanuel Manolas, Greece 2nd Com., www.problemiste.com, Problem 6, 1/2012

2R1RB2/bs1p1p2/5k1K/2pp1Pps/rPPp2P1/3p4/1r3P2/8 (9 + 13) #10

Try : {1.Re1?  [2.Be7#]  Re2!} Key : 1.f4! [2.Be7# / fxg5#] 1…gxf4 2.Be7+  Ke5 3.Bd8+ Kd6 4.Bc7+ Kc6 5.b5+ Rxb5 (the bRb2 goes away) 6.Bd8+ Kd6 7.Be7+ Ke5 8.Bf8+ Kf6 9.Re1 ~ 10.Be7# The travel of the black king is named pendulum. The problem is characterized Logical, that is what can not be done with the try, it appears again during the main solution of the problem.

Problem-711 Ioannis Kalkavouras, Greece Emmanuel Manolas, Greece MATPLUS 39-40, Autumn-Winter 2010, Problem 1675

5R2/5K2/2p2B2/2p2kpS/2p5/SPpb1P2/Pbs2p2/s2B1r2 (9 + 12) #8

Try : {1.Re8? [2.Re5#] Re1!} Key : 1.Sb5! [2.Sd6#] 1…cxb5 2.Rc8 [3.Rxc5#] Ba3 3.b4 [4.Rxc5#] Bxb4 4.Re8 [5.Re5#] Re1 5.Be2 [6.Re5#] Rxe2 6.Rg8 [7.Rxg5#] Re7+ 7.Kxe7 ~ 8.Rxg5# The problem is characterized Logical, that is what can not be done with the try, it appears again during the main solution of the problem.

Problem-712 János Mikitovics, Hungary Emmanuel Manolas, Greece juliasfairies.com 290

White : Kd3, Black : Kd6 Qh8 Re6 Bh3 Pd5h5g3, Neutral : Pe2, (1 + 7 + 1) The neutral pawn takes the color of the side which has the move. series auto-stalemate in 14 (White plays 14 moves and becomes stalemated). a) Diagram : condition Circe PWC (exchange of places during capture) b) +bRg5 : condition  KoBul Kings

a) 1.Kc2 2.e4 3.exd5(+bPe4) 4.dxe6(+bRd5) 5.e7 6.e8=nR (it is promoted to neutral Rook) 7.nRb8 8.nRxh8(+bQb8) 9.nRxh5(+bPh8) 10.nRh7 11.nRxh3(+bBh7) 12.nRh1 13.nRe1 14.nRxe4(+bQe1) auto= b) 1.Rd2 2.e4 3.Ke3 4.Kf4 5.exd5 6.dxe6(bK=bRK) 7.e7 8.e8=nB (it is promoted to neutral Bishop) 9.nBxh5(bRK=bK) 10.nBg4 11.Kxg3 12.Kh2 13.Kh1 14.nBxh3(bK=bBK) auto=

Problem-713 Vito Rallo, Italy Emmanuel Manolas, Greece variantim April 2013, problem 2363

8/8/8/8/8/1K2SP2/4k3/4s3 (3 + 2) h#3, 2 solutions, condition Andernach (= the capturer changes color)

1.Sxf3(=wSf3) Sd4+ 2.Kd2 Ka2 3.Kc1 Sb3# 1.Kd2 Sd5 2.Kd1 Kb2 3.Sxf3(=wSf3) Sc3# Ideal mates, Chameleon Mates (0,1), reversal of two black moves.

Problem-714 Vito Rallo, Italy Emmanuel Manolas, Greece juliasfairies.com 247

8/8/8/8/K7/pGG5/k7/s7 (3 + 3) (Grasshoppers b3 c3 + 0) h#3.5, Helpmate in 3.5 κινήσεις (that is white plays first) 2 solutions, Andernach (= the capturer changes color)

1…Gd3 2.Sc2 Ge3 3.Ka1 Kb3 4.Sxe3(=wSe3) Sc2# 1…Kb4 2.Sxb3(=wSb3) Sd2 3.Ka1 Kb3 4.a2 Ga3# In the same page of juliasfairies.com, there is the problem 248, another composition from the ones we create together with the Sicilian Vito Rallo.