In the next two versions we will see other reasonings which have led some composers to create new versions of some problems.
![]() | (Problem 79) Sam Loyd, ”Holyoke Transcript“, 1878 White plays and mates in 3 moves #3 (13+4) |
[8/6pK/4S1P1/1R1PP3/2PBkP2/3S2p1/6Pp/2R4Q] |
32 Tries: {1.Sf2+? gxf2!}, {1.Qxh2? Kxd3!}, {1.f5? Kxf5!}, {1.Kh8? / Kxg7? / Kg8? / d6? / Rbb1? / Rb2? / Rb3? / Rb4? / Ra5? / Rc5? / Rb6? / Rb7? / Rb8? / Bf2? / Ba7? / Bb6? / Bc5? / Sb2? / Se1? / Sc5+? / Sb4? / Qe1+? / Ra1? / Rcb1? / Rc3? / Rc2? / Rd1? / Re1+? / Rf1? Ke4-f5!}
Key: 1.Rg1!
1...Kxc3 2.Ra1 (Bristol line clearance) K~ / Kxc4 / Ke2 3.Qb1# / Qf1# / Qd1#
1...Kf5 2.Sf2 (zugzwang) gxf2 / hxg1=S 3.g4# / Qh5#
![]() | (Problem 80) C. Bull, 1878 White plays and mates in 3 moves #3 (11+5) |
[8/6pK/4p1P1/4P3/2P1kB2/1P1S2p1/4S1Pp/5R1Q] |
22 Tries: {1.Sf2+? gxf2!}, {1.Bc1? / Bd2? / Bg5? / Sxg3+? / Qxh2? Kxd3!}, {1.Kh8? / Kxg7? / Kg8? / Sb2? / Sc1? / Se1? / Sc5+? / Sb4? / Sc1? / Ra1? / Rb1? / Rc1? / Rd1? / Re1? / Rf3? / Rf2? Kf5!}.
Key: 1.Rg1!
1...Kxc3 2.Ra1 (Bristol line clearance) K~ / Kxe2 3.Qb1# / Qf1#
1...Kf5 2.Sf2 (zugzwang) gxf2 / hxg1=S 3.g4# / Qh5#
The key and the main variations of Loyd's problem have been preserved, but Bull's position is more economical, not so heavy in white forces.
![]() | (Problem 81) rev. Saavedra, (or position from the game [Fenton vs Potter]) 1875 White plays and wins + (2+2) |
[8/8/1KP5/3r4/8/8/8/k7] |
Key: 1.c7! Rd6+
2.Kb5
(Not Ka7, because after Rd7 the pawn is lost,
not Ka6 / Ka5, because after Rc6 the pawn is lost,
not Kc5, because after [Rd1 and Rc1+] the pawn (or the promoted piece) is lost).
2...Rd5+ 3.Kb4 Rd4+ 4.Kb3 Rd3+ 5.Kc2
(Now the plan [Rd1 and Rc1+] is not applicable).
5...Rd4!
(Tricky move, because if 6.c8=Q Rc4+ 7.Qxc4 forced, and black is stalemated!)
6.c8=R [7.Ra8#] Ra4 7.Kb3 [8.Kxa4 / Rc1#] ± (white wins).
![]() | (Problem 82) A. A. Troitzky, ”Ceske Slovo”, 1924 White plays and wins + (5+5) |
[8/3b4/k2p3P/1p1K3P/1P4r1/8/3R4/8] |
Key: 1.h7! Rg5+ 2.Kxd6 Rxh5 3.Kc7 [4.Ra2#] Be6 4.Kb8 [5.Rd6#] Bd5 5.Rxd5 Rxd5
6.h8=R [7.Rh6#] Rd6 7.Kc7 [8.Kxd6 / Ra8#] ± (white wins)
Troitzky has taken Saavedra's idea and has presented it in new form.
(This post in Greek language).
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