Six problems were presented to solvers (1 two-mover, 1 three-mover, 1 more-mover in 4, a study, a help-mate four-mover, a self-mate three-mover) with a time limit 2,5 hours.
The final ranking of the solvers : Spiliadis Athanassios 14.0/30.0, Terzis Philippos 05.0, Sboukis Konstantinos 5.0, Sboukis Athanassios 05.0, Stamatopoulos Apostolos 04.0, Leftheriotis Aimilios , Stamatopoulos Georgios, Kontogiannis Georgios.
Here follow the problems and their solutions. Each problem takes 5 grades and we show in square brackets how many grades are given to the key, to the threat and to each variation.
![]() | (Problem 463) Heinonen, Unto, First Prize, ST 2002, Mate in 2 moves. #2 (9 + 10) |
[2B3ss/1K3pRr/1ppk4/4R2P/b3PQ2/3p1S2/1S6/2q5] |
Key : 1.Qg5! [5.0] ( > 2.Qd8# ) c5 / f6 2.Rd5# / Re6#
![]() | (Problem 464) Chocholouš, Jiři, Second Prize, Tidskrift för Schack, 1903, Mate in 3 moves. #3 (6 + 11) |
[2b5/p1p4K/Pp2p3/3pk3/1Q3R2/p5pp/4P2r/2B5] |
Key : 1.Be3! [1.0] ( > 2. Rf3 ( > 3.Qf4# ) ) d4 3.Qxd4# [1.0]
1...Rf2 2.Rxf2 [1.0] d4 3.Qxd4#
1...c5 2.Bxc5 [1.0] bxc5 3.Qb8#
1...Bxa6 2.Rf5+ [1.0] Kxf5 3.Qf4# / Qe7#
![]() | (Problem 465) Juchli, Josef, Augsburger Abendzeitung, 1885, Mate in 4 moves. #4 (8 + 11) |
[6b1/SB1R1p2/1p2p3/4k1P1/2p3P1/s2p3p/1P1B2p1/3K2s1] |
Key : 1.Ba8! zugzwang [1.0]
1...Sa3 ~ 2.Sc6+ Ke4 3.Sa5+ [0.5] Ke5 4.Sxc4#
1...Sg1 ~ 2.Sc6+ Ke4 3.Sd4+ [0.5] Ke5 4.Sxf3#
1...h2 2.Bxg2 Sf3 3.Sc6+ [0.5] Ke4 4.Rd4#
1...c3 2.Sc6+ Ke4 3.Sb4+ [0.5] Ke5 4.Sxd3#
1...b5 2.Bd5 Kd4 3.Sc6+ [0.5] Kc5 4.Be3#
2...exd5 3.Re7+ [0.5] Kd6 / Kd4 4.Bb4# / Be3#
1...f7 ~ 2.Sc6+ Ke4 3.Se7+ [0.5] Ke5 4.Sg6#
1...Bh7 2.Sc6+ Ke4 3.Sd8+ [0.5] Ke5 4.Sxf7#
![]() | (Problem 466) Michelet, Paul, BCM, 2010, White plays and draws. = (4 + 3) |
[8/8/8/3B1k2/K7/8/Pp2b1S1/8] |
Key : 1.Se3+ [1.0] Ke5 / Kf4
2.Be4! [1.0] Kxe4
3.Sd1!! [2.0] Bxd1
4.Ka3 d1=Q/R? = stalemate
4...d1=B? = draw, since both bishops are white-squared
4...d1=S
5.Kb2 Sd2
6.Kc1 [1.0] = draw, since one light piece will be captured
![]() | (Problem 467) Feather, Chris, Broodings, 2008, Helpmate in 4 moves. Two solutions. h#4 2.1.1.1.1.1.1.1 (4 + 5) |
[8/7s/4SB2/4Pbs1/4k3/6p1/8/K7] |
1.Sxe6 Bd8 2.Sg7 e6 3.Ke5 e7 4.Kf6 e8=Q# [2.5]
1.Sxf6 exf6 2.Bh7 f7 3.Kf5 f8=Q+ 4.Kg6 Sf4# [2.5]
![]() | (Problem 468) Zabunov, Vladimir N., , Selfmate in 3 moves. s#3 (12 + 12) |
[7b/1Q2R3/PpPkPp1r/1p5p/2pKPR1S/1q1pP2B/7B/3s1r2] |
Key : 1.Re8! [1.0] ( > 2.Qe7+ Kxc6 3.Qc5+ bxc5# )
1...Sxe3 2.Rg4+ Rf4 3.Sf5+ [1.0] Sxf5#
1...c3 2.Rf5+ Rf4 3.Rd5+ [1.0] Qxd5#
1...Rh7 2.Rxf6+ Rf4 3.e7+ [1.0] Bxf6#
2 comments:
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Is this possible?
@Anonymous
You do not give details about yourself or your site. Should I discard your anonymous message? Anyway...
I accept only sites relevant with chess problems.
If you post news about games of chess, I am not interested.
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