(Problem 30) Magazine “Lexorama #5” White plays and mates in 3 moves #3 (4+2) | |
[8/P7/8/5R2/4p3/8/2K1kB2/8] |
Try: {1.a8=Q? Kf1!}
Key: 1.a8=B!
1...Kf1 2.Be4 Ke2 3.Bd3#
1...e3 2.Bg2 exg2 3.Re5#
(Problem 31) Sam Loyd, ”Holyoke Transcript”, 1876 White plays and mates in 3 moves #3 (6+3) | |
[ b7/PP6/8/8/7K/6B1/6S1/4R1bk] |
Try: {1.bxa8=Q? (Black is in stalemate! No legal move exists for black, and that means white has lost the opportunity to win)}.
Key: 1.bxa8=S! Kxg2 2.Sb6 ~ 3.a8=B/Q#
Comments: Here the key takes a piece (we today believe this is not a good first move for an orthodox problem), sacrificing at the same time Sg2 (and the composer believes that this brings equilibrium).
Anyway, the key presents a clever underpromotion: The white knight Sa8 is needed to protect pawn a7, which will be threatened from the black bishop Bg1, just when bishop is unpinned.
The composer believes that is not a defect, that in the last move of the solution the promoted piece can be B or Q.
(Problem 133) Endre Ancsin, 3rd Prize, ”Internationaler Mannschaftswettkampf”, 1936/37 White plays and mates in 3 moves #3 (13+13) | |
[2ss3B/2SpPp1B/K4Qq1/1R4r1/pb2kpP1/1r3pP1/2PPbP2/4R3] |
We see a white rook pinned by a black bishop, which is pinned by a white rook. We also see a white queen pinned by a black queen, which is pinned by a white bishop.
Try: {1.d3+? Rxd3!}
Try: {1.Rxe2+? fxe2!}
Try: {1.Bxg6+? Rxg6! (and the queen remains pinned)}.
Key: 1.e8=S! [2.Sd6+ Bxd6 / Sxd6 3.Qd4#]
If 1...Rd3 2.Rxb4+ Rd4+ 3.d3#
If 1...Se6 2.Qd4+ Sxd4+ 3.Sf6#
In the variations of the solution we observe cross-checks. The white gives check, the black answers with check, the white answers again with check.
[This post in Greek language].
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